Question

the mass of limestone on thermal decomposition yield 5600 ml of co2 gas at stp is

Answer 1

it is correct question

Answer 2

Mass of limestone is 25 g

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

$PV=nRT$

where,

P = pressure of the gas  = 1atm (at STP)

V = volume of the gas  = 5600 ml =5.6 L (1L=1000ml)

T = temperature of the gas  = 273 K (at STP)

n = number of moles of gas

R = Gas constant

$1atm\times 5.6L=n\times 0.0821Latm/Kmol\times 273K$

$n=0.25moles$

$CaCO_3(s)\rightarrow CaO(s)+CO_2(g)$

Accordig to stoichiometry:

1 mole of $CO_2$ is produced from 1 mole of $CaCO_3$

250 moles of $CO_2$ is produced from=$\frac{1}{1}\times 0.25=0.25moles$ of $CaCO_3$

Mass of  $CaCO_3=moles\times {\text {molar mass}}=0.25mol\times 100g/mol=25g$

Thus mass of limestone is 25 g

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