Question

Hi Friends ....
Good Afternoon ....

Please answer this question :-

0.40 of an organic compound gave 0.30 of silver bromide by Carius method . Determine the percentage of bromine in the compound .
At . masses : Ag = 108 . Br = 80

Thank You ...
^_^

Answer 1

Hello Anaida.....It's Your Friend Aditi here^_^

Mass of organic compound = 0.40

Mass of AgBr formed = 0.30

Molar mass of AgBr = 108+ 80 = 188 g.

So 188g of AgBr contains 80 gram Bromine.

0.3 g of AgBr will contain (80 / 188)*0.3 = 0.127 g of Br.(By Unitary method).

Therefore....Percentage of Br in the compound = (0.127 / 0.40)* 100 = 31.91 percentage.