Question

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$\bf\sqrt{2}x^{2}\:-3x+3\sqrt{2}=0$

find x by quadratic equation

Answer 1

$\sqrt{2} \: {x}^{2} - 3x + 3\sqrt{2} = 0 \\ wkt \: \\ for \: a {x}^{2} + bx + c = 0 \\ x = \frac{ - b + | \sqrt{ {b}^{2} - 4ac } | }{2a} \\ now \: here \\ x = \frac{3 + | \sqrt{ 9 - 4 (3)\sqrt{2} \sqrt{2} }| }{2 \sqrt{2} } \\since\:i^{2} = -1 \\x = \frac{3 + |\sqrt {15}i| }{2 \sqrt{2} } \\ x = \frac{3 +\sqrt {15}i}{2 \sqrt{2} } \\ x = \frac{3 -\sqrt {15}i}{2 \sqrt{2} }$
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