Question

hi friends please give fast answer I will mark as brainliest​

Answer 1

Answer:

I)

1. -9

2. 125

3. 1/16

4. 1/8

5. 1/32

2)

1. 4

2. 1/12

3. 59,049

4. 1/36

5. 1

6. 1/2

7) 1

Step-by-step explanation:

plz make me brainliest

Answer 2

Answer:

Step-by-step explanation:

(i)

1) $3^{(-2)}$

$=(\frac{1}{3})^{(2)}$  --------------------( a^-m = (1/a)^m )

$\\=\frac{1^{2} }{3^{2} } \\\\=\frac{1}{9}$

2) 5^3=5x5x5=125

3) $(-4)^{(-2)}$

= $(\frac{1}{-4} )^{(2)}$ --------------------( a^-m = (1/a)^m )

$=\frac{1^2}{-4^2} \\\\=\frac{1}{16}$

4) $2^{(-3)}$

$=(\frac{1}{2})^{3}$ --------------------( a^-m = (1/a)^m )

$= \frac{1^3}{2^3} \\\\=\frac{1}{8}$

5)$2^{(-5)}$

$=(\frac{1}{2} )^5$ --------------------( a^-m = (1/a)^m )

$=\frac{1^5}{2^5}$

= $\frac{1}{32}$

(ii)

1) $2^0 + 2^2$

= 1+2 -----------------($a^0$ = 1)

=3

2) $3^{(-1)}$ x $4^{(-1)}$

= $(\frac{1}{3} )^1$ x $(\frac{1}{4} )^1$      --------------------( a^-m = (1/a)^m )

= $\frac{1}{3}$ x $\frac{1}{4}$

=$\frac{1}{12}$

3) $(3^2)^5$

=$(3)^5^*^2$ --------------------( $(a^m)^n = (a)^m^*^n$)

=$(3)^1^0$  

= 59049

4)$\frac{2^{(-2)}}{3^{2}}$

=$(\frac{1}{2})^{2}$ x $\frac{1}{9}$ ---------------------(a^-m = (1/a)^m )

=$\frac{1^{2}}{2^{2}}$x $\frac{1}{9}$

=$\frac{1}{4}$x $\frac{1}{9}$

=$\frac{1}{36}$

7)$(3^{-1} + 4^{-1}+5^{-1})^0$

= 1 ----------------------------($a^0$ = 1)

5)$(3^{0}+4^{-1})$ x $2^{2}$

=$(1+(\frac{1}{4})^1)$ x $2^{2}$ --------------------------------(a^-m = (1/a)^m )

=$\frac{4+1}{4}$ x $2^2$

=$\frac{5}{4}$ x $2^2$

=$\frac{5}{4}$ x 4

= 5

6) ($2^{-1}$ x $4^{-1}$) ÷ $2^{-2}$

= $\frac{8^{-1}}{2^{-2}}$

= $\frac{2^{2}}{8^{1}}$ ------------------------------((a^-m/b^-n = b^n/a^m )

$=\frac{4}{8}\\ \\=\frac{1}{2}$

pls mrk as brainliest plss i took soo much time to answer ur question and no one is not mrking me brainliest :( even after i write for them..... soo pls atleast u mrk :)