Hi friends please help me in this question :
Book : M.L. Aggarwal
Class: 9
Question 1:
A rectangular plot of land measures 41 metres in length and 22.5 metres in width. A boundary wall to metres high is built all around the plot at a distance of 1.5 m from the plot. Find the inner surface area of the boundary wall.
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Step-by-step explanation:
GIVEN:-
The wall is built 1.5 m from the plot so the length and width of wall will be
41 + 2(1.5) = 44m
22.5 + 2(1.5) = 25.5m.
TO FIND:-
Inner surface area of the boundary wall
PROOF:-
Inner area of wall
= 2h (l + b)
= 2 (2) (44 + 25.5)
= 278m^2
ANSWER:-
The inner surface area = 278m^2
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Step-by-step explanation:
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