Question

HI friends....✌️
Pls answer this math question only if u know...or else..pls leave it...​

Answer 1

❥${\red{\underline{\huge{\mathbb{Solution:-}}}}}$

$\frac{1}{(x - 1)(x - 2)} + \frac{1}{(x - 2)(x - 3)} = \frac{2}{3 }$

Apply the rule of separation.

$= > \frac{1}{(x - 2)} - \frac{1}{(x - 1) } + \frac{1}{(x - 3)} - \frac{1}{(x - 2)} = \frac{2}{3} \\ = > \frac{1}{(x - 3)} - \frac{1}{(x - 1)} = \frac{2}{3 } \\ = > \frac{(x - 1) - (x - 3)}{(x - 3)(x - 1)} = \frac{2}{3} \\ = > \frac{x - 1 - x + 3}{ {x}^{2} - 4x + 3} = \frac{2}{3} \\ = > \frac{2}{ {x}^{2} - 4x + 3} = \frac{2}{3} \\ = > 2 {x}^{2} - 8x + 6 = 6 \\ = > 2 {x}^{2} - 8x = 6 - 6 \\ = > 2 {x}^{2} - 8x = 0 \\ = > 2x(x - 4) = 0 \\ = > x - 4 = 0 \\ = > x = 4$

★Answer:-

$x = 4$

Answer 2

HI ABHI......!

...x = 0, x = 4

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NAALE ALLE EXAM....

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PWOLICH EZUTH...✌️