Question

hi friends plz help me to solve this problem
the average age of 10 member of a committee is same as it was 4years ago because an old member has been replaced by a young member

find how much younger is the new member?????

Answer 1

Hy mate____________________
___________________

◀ Here is your solution ▶
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First step. 1
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➡ the sum of nine member (total) =x
AND
➡ the age of old one =z

second step .2
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➡ its average 4 years.
before=(x+z)/10.

➡ after 4 years
➡ let z be replaced by y.

➡ now avg=(x+4*10+y)/10

now (x+z)/10=(x+40+y)/10
so after solving it found
z=y+40.
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so old person is 40yrs older than.
young one.


⭐ Thankyou. ⭐
Brainly user

Answer 2

Hey sis......................................
...............................

Thats your perfect solution...

Let the members be Old Having age O + other 9 having ages x and New one having age Y

Sum of their ages = (Y + 9 × x)
and
average = (Y + 9 × x)/10

Before 4 years sum was
(O + 9 x – 10 × 4)
and
average = (O + 9 x – 10 × 4) /10

equating, Y + 9 x = O + 9x – 40
Y = O – 40
Younger is 40 years younger than Old one.


Thankyou...............
Be brainly..............