hi guys Corona please stay at home and solve my question and I am from nepal
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Step-by-step explanation:
- Given a + b + c = m
- So a + b = m – c
- Also a + c = m – b
- So b + c = m – a
- Now x^2a / x^2a + x^a + b + x^a + c + x^2b / x^2b + x^b + c + x^a + b + x^2c / x^2c + x^a + c + x^b + c
- We can write x^2a as x^a. x^a , x^2b as x^b.x^b, x^c as x^c.x^c
- We get
- So it will be x^a / x^a + x^b + x^c + x^b / x^a + x^b + x^c + x^c / x^a + x^b + x^c
- = x^a + x^b + x^c / x^a + x^b + x^c (by taking LCM)
- = 1
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https://brainly.in/question/6523335
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