Math, asked by Anonymous, 11 months ago

Hi guys.....Help me in Q no. 21

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Answered by Anonymous
1

Answer:

(a) AC² = AL² + CL²

= ( AD² - DL² ) + CL²

= AD² + ( CL² - DL² )

= AD² + ( CL - DL ) ( CL + DL )

= AD² + CD ( CD + DL + DL )

= AD² + CD ( CD + 2 DL )

= AD² + ( 2 CD ) DL + CD²

= AD² + BC · DL + ( BC / 2 )²


(b) AB² = AL² + BL²

= ( AD² - DL² ) + BL²

= AD² + ( BL² - DL² )

= AD² + ( BL + DL ) ( BL - DL )

= AD² + BD ( BD - DL - DL )

= AD² + BD ( BD - 2 DL )

= AD² - ( 2 BD ) DL + BD²

= AD² - BC · DL + ( BC / 2 )²


(c) This is just adding the expressions for AC² and AB² from (a) and (b) above.


Answered by Anonymous
2
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