Math, asked by anitayadav3613729, 3 months ago

Hi guys please help me in this question
Book: M.L Aggarwal [Pg-364, Question:18]
Class:9
Question 1:
The length and the breadth of a rectangle are 12 cm and 9 cm respectively.Find the height of a triangle whose base is 9 cm and whose area is one-third that of rectangle.

Answers

Answered by ltzSweetAngel
1

=> Area of rectangle = Length × Breadth

Length = 12 cm

Breadth = 9cm

12cm×9cm = 180cm²

=> area of triangle = 1/3 of the area of rectangle

=1/3 ×180 = 36cm²

area of triangle = 1/2 base × height

36=1/2×9×height

Height = 8 cm

Answered by arunpatodi18
1

Area of rectangle=length*breadth

= = 12 * 9 = 108 cm?

Area of triangle=1/3 of area of

rectangle

=1/3 * 108 = 36cm2

Area of triangle=1/2 base × height

36 =1/2*9*height

height =8 cm (ans)

Step-by-step explanation:

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