Question

hi guys please solve it . it's very urgent

Answer 1

Q: Show that (1) ∆ABM is congruent to ∆PQN
(2) ∆ABC is congruent to ∆PQR
=> Given :
AB = PQ -(1)
BC =QR -(2)
AM= PN -(3)
.°. AM is the median of ∆ABC
BM = CM = ½BC
Also, PN is the median of ∆PQR
So, CAN = RN =½QR

To prove : ∆ABM is congruent ∆PQN
Proof: Since, BC = QR
½BC =½QR
BM = QN -(4)
In, ∆ABM & ∆PQN,
AB = PQ (from -1)
AM = PN (from -3)
BM = QN (from -4)
So, ∆ABM is congruent ∆PQN

(FROM S-S-S congruence rule)