Hi Guys, plz answer to 14 and 15.
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And what about 13 question???
sorry i actually needed the 15 answer!!!
Question no 15: If a+b = 10 and a sq + b sq = 58, find the value of a cube + b cube. Plz answer
No need of 13 question
Thankyou
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Let p(x) = ax³ + bx² + x - 6
A/C to question,
(x + 2) is the factor of p(x) , and we know this is possible only when p(-2) = 0
So, p(2) = a(-2)³ + b(-2)² - 2 - 6 = 0
⇒-8a + 4b - 8 = 0
⇒ 2a - b + 2 = 0 -------------(1)
again, question said that if we p(x) is divided by ( x -2) then it leaves remainder 4.
so, P(2) = a(2)³ + b(2)² + 2 - 6 = 4
⇒8a + 4b - 4 = 4
2a + b -2 = 0 -------------(2)
solve equations (1) and (2),
4a = 0 ⇒a = 0 and b = 2
Then, equation will be 2x² + x - 6
hope this helps....
Answer this question Plz
a+b=10
a^2+b^2=58
a^3+b^3=??
(a+b)^2=a^2+b^2+2ab
(10)^2=58+2ab (by putting the values)
100=58+2ab
100-58=2ab
42=2ab
42/2=2ab
21=2ab
now we will find a^3+b^3
a^3 + b^3 = (a + b)^3 − 3ab(a + b)
a^3 + b^3 = (10)^3-3*21(10) (by putting the values)
a^3 + b^3 = 1000-63*10
a^3 + b^3 = 1000-630
a^3 + b^3 = 370
hope this helps..
a^2+b^2=58
a^3+b^3=??
(a+b)^2=a^2+b^2+2ab
(10)^2=58+2ab (by putting the values)
100=58+2ab
100-58=2ab
42=2ab
42/2=2ab
21=2ab
now we will find a^3+b^3
a^3 + b^3 = (a + b)^3 − 3ab(a + b)
a^3 + b^3 = (10)^3-3*21(10) (by putting the values)
a^3 + b^3 = 1000-63*10
a^3 + b^3 = 1000-630
a^3 + b^3 = 370
hope this helps..
mark me as the brainliest answer..
plzz....
why didnt u mark me as the brainliest answer..
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