Question

hi guys

tell me the area of quadrilateral ABCD , where BD = 22 cm, CE = 7 cm and AF = 6 cm. ​

Answer 1

Step-by-step explanation:

area of ABCD=area of ABD+area of BCD

Area of ABD=1/2×b×h=1/2×BD×AF=1/2×22×6=66cm^2

Area of BCD=1/2×b×h=1/2×BD×CE=1/2×22×7=77cm^2

Area of ABCD=(66+77)cm^2=143cm^2