Hi , here is Riddle
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@ Ranjan Kumar
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★ HERE IS YOUR ANSWER ★
In the 1st figure each hen is equal to 20
So, 20 + 20 + 20 = 60
In the 2nd figure each egg is equal to 3
So, 20 + 3 + 3 = 26
In the 3rd figure one bunch of banana is equal to 6
So, 3 + 6 + 6 = 15
Now, Hen = 20 ; Egg = 3 ; Banana = 6
So, 20 + 3 × 5 = 35
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In the 1st figure each hen is equal to 20
So, 20 + 20 + 20 = 60
In the 2nd figure each egg is equal to 3
So, 20 + 3 + 3 = 26
In the 3rd figure one bunch of banana is equal to 6
So, 3 + 6 + 6 = 15
Now, Hen = 20 ; Egg = 3 ; Banana = 6
So, 20 + 3 × 5 = 35
☆ Please mark it brainliest if its helpful ☆
Answered by
96
Hey..!
Answer :-
From first figure,
Let hens be x
Then,
x+x+x = 60
=> 3x = 60
=> x = 60/3
=> x = 20
Hence the value of hen is 20
From second figure,
x + y +y = 26
We know , x = 20 then ..
=> 20 + 2y = 26
=> 2y = 26-20
=> 2y = 6
=> y =6/2
=> y = 3
Hence the value of egg is 3
From figure three...
Let bananas = z
=> y + z + z = 15
=> y = 3
=> 3 + 2z = 15
=> 2z = 15-3
=>2z = 12
=> z = 12/2
=> z = 6
Now last figure...
=> hen + eggs * banana = ?
=> we know hen = 20
Eggs = 3
Banana = 5 since one banana is less.
Then ..
=> 20 + 3 * 5
As per BODMAS rule ..
=> 20 + 15
=> 35
Hope this helps
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