If x cube +x square -ax+b is divisible by x square - x write the values of a and b
Answers
Answered by
8
Hi friend
The equation is devided by x^2 -x and leave no remainder it means roots of the equation
X^2 - x = 0 ... Are also roots of the given equation x^3 + x^2 - ax +b =0
x^2 -x = 0
X(x-1) =0
X = 0 and x-1 =0
Roots x = 0 & 1
Put in given equation
X= 0
(0)^3 + (0)^2 - a(0) + b =0
B =0
Put x=1
(1)^3 + (1)^2 -a(1) + b =0
1+1-a+0=0
a = -2
Hope it help you!!
The equation is devided by x^2 -x and leave no remainder it means roots of the equation
X^2 - x = 0 ... Are also roots of the given equation x^3 + x^2 - ax +b =0
x^2 -x = 0
X(x-1) =0
X = 0 and x-1 =0
Roots x = 0 & 1
Put in given equation
X= 0
(0)^3 + (0)^2 - a(0) + b =0
B =0
Put x=1
(1)^3 + (1)^2 -a(1) + b =0
1+1-a+0=0
a = -2
Hope it help you!!
Answered by
2
Answer:
Step-by-step explanation:
Hi friend
The equation is devided by x^2 -x and leave no remainder it means roots of the equation
X^2 - x = 0 ... Are also roots of the given equation x^3 + x^2 - ax +b =0
x^2 -x = 0
X(x-1) =0
X = 0 and x-1 =0
Roots x = 0 & 1
Put in given equation
X= 0
(0)^3 + (0)^2 - a(0) + b =0
B =0
Put x=1
(1)^3 + (1)^2 -a(1) + b =0
1+1-a+0=0
a = 2
Similar questions