Hi , If possible please solve this question
N Avasthi .
standard => 11th
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Anonymous:
option a ??
Answers
Answered by
8
PH = - log (base10) [H+] = 4.3
log ( base 10) [H+]^-1 = 4.3
10^ 4.3 = [ H+]^-1
[H+] = 10^-4 .3
10^ -4 × 10^ -0.3
As 10^ -0.3 = 0.5
So 0.5 × 10^-4
5 × 10^ -5
log ( base 10) [H+]^-1 = 4.3
10^ 4.3 = [ H+]^-1
[H+] = 10^-4 .3
10^ -4 × 10^ -0.3
As 10^ -0.3 = 0.5
So 0.5 × 10^-4
5 × 10^ -5
Answered by
3
If pH is 4.30
Then
{H+}=>10^-4.3
which is
=>10^-4×10^-3
=>10^-4×0.5
=>5.0×10^-5
Then
{H+}=>10^-4.3
which is
=>10^-4×10^-3
=>10^-4×0.5
=>5.0×10^-5
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