Question

Hi!❤
If the side of the square be increased by 50%. Then find the percentage increase in the area of the square.
Answer is 125%. Please show solution...
Thanks

Answer 1

Answer:done in image

Step-by-step explanation:

In $\fbox{attachment}$

Hope it helps you.............

Answer 2

Hey mate ^_^

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Answer:
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Let the side of the square be $'x'$

Area of square = $side^2$ $= x^2 \: unit$

Now,

50% of the side = $\frac{x}{2}$

New side,

$= \frac{x + x}{2}$

$= \frac{3x}{2}$

Area of a square (New side)

$= \frac{3x}{2^{2} }$

$= \frac{9x^{2} }{4}$

Now,

Increased percentage

$= \frac{Increased \: Area}{Actual \: Area} \times 100$

Therefore,

Increased area

$= \frac{9x^{2} }{4} - x^{2}$

$= \frac{5x^{2} }{4}$

Increased percentage,

$= \frac{5x^{2} }{4} \div {x}^{2} \times 100$

$= 125\%$

Answer: 125%

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