Question

hi

In an examination 96% of the candidates passed, and 50 failed how many candidates appeared?


Answer plzz

First answer will be brainlest

Answer 1

Hi there!

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Solution :

Let the number of candidates appeared be x.

Percentage of those who passed = 96 %

Percentage of those who failed

⇒ ( 100 - 96 )%

⇒ 4 %

Number of failures = 4% of x.

∴ 4 % of x = 50

⇒ 4 / 100 * x = 50

⇒ x / 25 = 50

⇒ x = 25 × 50

⇒ x = 1250.

Hence,

The number of candidates appeared is 1250.

Alternative method :

Let the number of candidates appeared be 100.

Then,

The number of candidates who passed = 96.

Number of failures = (100 - 96) = 4

If there are 4 failures, then total number of candidates = 100.

If there are 50 failures, then total number of candidates

⇒ ( 100 / 4 × 50)

⇒ ( 25 × 50 )

⇒ 1250.

Hence,

The number of candidates appeared is 1250.

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Thanks for the question !

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Answer 2

Hello friend ✌️✌️

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Let us take no of candidates be x.

Those who passed = 96 %

Those who failed = 4 %

No of failed candidates = 4% of x

∴ 4 % of x = 50

⇒ 4x / 100 = 50

⇒ 4x = 5000

⇒ x = 1250

Hence, the no of candidates = 1250.

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Hope it helps ☺️❤️☺️