Math, asked by Anonymous, 1 year ago

Hi mates!!

Answer my question!

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Answers

Answered by RAJPUTANALIONS
6
bhai pehle tanQ Ko aur cotQ ko break kro aur uske bad ye process hai
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Answered by Brainlyconquerer
3

Step-by-step explanation:

\implies  \frac{ \cos(a) }{1 -  \tan(a) }  +  \frac{ \sin(a) }{1 -  \cot(a) }  = \sin(a)    +  \cos(a)  \\  \\  \implies  \frac{ \cos(a) }{1 -  \frac{ \sin(a) }{ \cos(a) } }  +  \frac{ \sin(a) }{1 -  \frac{ \cos(a) }{ \sin(a) } }  \\  \\  \implies  \frac{  \cos(a)  \times  \cos(a) }{ \cos(a) -  \sin(a)  }  +  \frac{ \sin(a) \times  \sin(a)  }{ \sin(a) -  \cos(a)  } \\  \\   \implies  \frac{ { \cos(a) }^{2} }{ \cos(a) -  \sin(a)  }   -  \frac{ { \sin(a) }^{2} }{ \cos(a)  -   \sin(a)  }  \\  \\   \implies  \frac{ { \cos(a) }^{2}  -  { \sin(a) }^{2} }{ \cos(a) -  \sin(a)  }  \\  \\   \implies  \frac{ (\cos(a) +  \sin(a) )\times (  \cos(a)   -  \sin(a) }{ \cos(a)  -  \sin(a) }  \\  \\ \implies   \sin(a)  +  \cos(a)

hence proved.

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Identities Used :-

✴ a² - b² = (a + b )( a - b )

✴ Tanx = sinx / cosx

✴ Cotx = cosx / sinx

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