Math, asked by shipra2250, 1 year ago

hi mates.....pls solve these....

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Answered by zaidazmi8442
1
Udayraj is right for this question

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Answered by udayraj768oy9yd5
1

Answer:

three points be collinear when area of triangle formed by meeting of all three points = 0

The points A(a , a²) , B( b, b²) and C( c, c²) are given.

so, area of triangle ABC = 1/2[a( b² - c²) + b(c² - a²) + c(a² - b²)]

= 1/2[ab² - ac² + bc² - ba² + ca² - cb² ]

= 1/2 [ ab(b - a) + bc(c - b) + ca(a - c)]

Here it is clear that area of triangle be zero when a = b = c . but a ≠ b ≠ c , so, area of triangle can't be zero. That's why all the given three points are never be collinear.

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shipra2250: A ke points (x1 ,y1) and B ke (x2y2),and c ke (x3y3 ) nhi le skte???
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