hi ..
my new question ..
Find the area of triangle in which each side is like this .
a = 13cm b= 14 c= 15
Answers
Answered by
16
A=13,
b=14,
c=15
S=a+b+c/2
=13+14+15/2
=21cm
Area=root over of21*8*7*6
=3*7*7*2*2*2*2*3=3*2*2*7
=84cm sq.
OR
By using herons formula
We get
s=13+14+15/2
S=21cm
Now area=√s(s-a) (s-b) (s-c)
√21(21-13)(21-14)(21-15)
√21(8)(7)(6)
√21(336)
√7056
84 cm² is the area
b=14,
c=15
S=a+b+c/2
=13+14+15/2
=21cm
Area=root over of21*8*7*6
=3*7*7*2*2*2*2*3=3*2*2*7
=84cm sq.
OR
By using herons formula
We get
s=13+14+15/2
S=21cm
Now area=√s(s-a) (s-b) (s-c)
√21(21-13)(21-14)(21-15)
√21(8)(7)(6)
√21(336)
√7056
84 cm² is the area
rohankaitake95:
Hi anu
Answered by
8
Answer:
here is ur required answer
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