Question

hi .please answer for my question. please please please​

Answer 1

Since AD=BD

Triangle ABD is an isocelese triangle

then angle ABD = angle BAD = 50°

=> 50 + 50 + angle ADB = 180°

=> angle ADB = 80°

NOW,

angle ADB + angle ADC = 180. [Linear pair]

=> 80 + angle ADC = 180°

=> angle ADC = 100°

also since AD = DC

Triangle ADC is also an isoscelese triangle

then

angle ACD = angle DAC = X ( Let )

now,

=> X + X + angle ADC = 180°

=> 2X + 100 = 180

=> 2X = 80

=> X = 40°

THEREFORE ANGLE ACD = 40°