Question

Hi !! Please solve the sum which is in attachment.
please solve it in notebook!
Spammers stay away !
Thank you in advance .✨​

Answer 1

Answer:

3

Step-by-step explanation:

$5 \sin(90 - 28 ) \div \cos(28) - 2 \sec(90 - 56) \div \cosec(56)$

As we know,

sin(90 - x) = cosx and sec(90 - x) = cosecx

$5 \cos(28) \div \cos(28) - 2 \cosec(56) \div \cosec(56)$

Now , cos28 and cosec56 will get cancelled,

$5 - 2$

$3$