Question

hi please tell me this ... with pic of this solution i dont want irreverent answers​

Answer 1

Explanation:

Let the present population be 2 lakh

then,

population can be consider as principal

So,

P = 200000

R = 8 %

T = 2 yre

SI = P×R×T ÷ 100

= 200000×8×2÷100 = 32000

Then the population after two year will be = 200000+32000

= 232000

Answer 2

Explanation:

$let,\: \\ present \: population \: of \: my\: birth\: place=x \\ rate \: of \: increasement \: (r) = 8\% \: p.a. \\ time \: (n) = 2 \: years \\ population \: after \: 2 \: years = p( {1 + \frac{r}{100} })^{n} \\ = x ({1 + \frac{8}{100}})^{2} \\ = x ({ \frac{108}{100} })^{2} \\ = x ({ \frac{27}{25} })^{2} \\ population \: after \: 2 \: years = \frac{729x}{625}$

put the value of x according to your birth place.

and you will get your answer.

hope it helps you

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