Question

Hi....pls answer
50 points and brainliest answer as well assured

Answer 1

Given, (a+b)²/ab+(b+c)²/bc+(c+a)²/ac

and, a+b+c = 0

So, a+b = -c , b+c = -a , a+c = -b

Substituiting the values into the expression

(-c)²/ab + (-a)²/bc + (-b)²/ac

= c³/abc + a³/abc + b³/abc

= a³+b³+c³/abc

As a+b+c = 0 , So a³+b³+c³ will be equal to 3abc

= 3abc/abc

= 3

Hope it helps.

Thanks!!!