Math, asked by niya25, 1 year ago

hi
solve this_______€I will Mark u brainlist

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Anonymous: 3 c^2 - 3c - 14 c + 14 = 3 c( c-1) - 14 ( c - 1 ) = ( 3c - 14) ( c - 1)
Anonymous: 3c - 14 =0, c = 14 /3
Anonymous: c-1 = 0, c = 1
Anonymous: So, c = 1 is more admissible

Answers

Answered by sg2544
2
hello mate!............


given........


3c {}^{2}  - 17c + 14 = 0 \\  \\ 3c {}^{2}  - 14c - 3c + 14 = 0 \\  \\ 3c {}^{2}  - 3c - 14c + 14 = 0 \\  \\ 3c(c - 1) - 14(c - 1) = 0 \\  \\ (c - 1)(3c - 14) = 0 \\  \\ c = 1 \: an d \:  \frac{14}{3}
hope it helps u dear......
Answered by sanjay7078
1
I think it helps you dear

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