Hi!!!
solve this question(explanation is needed)
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Hey there !!
▶Given :-
→ PQR is a right angle triangle .
→ Right angle at p .
→ PM
QR .
▶ To prove :-
→ PM² = QM • MR .
▶ Solution :-
We know that :
If a perpendicular is drawn from the vertex of the right angle of a right triangle to the hypotenuse then the triangles on both sides of the perpendicular and similar to the whole triangle and also to each other.
![\sf \therefore \triangle PQM \sim \triangle RPM. \\ \\ \sf \implies \frac{PM}{MR} = \frac{QM}{PM} . \\ \\ \boxed{\boxed{ \green{ \sf \implies {PM}^{2} = QM.MR \: .}}} \sf \therefore \triangle PQM \sim \triangle RPM. \\ \\ \sf \implies \frac{PM}{MR} = \frac{QM}{PM} . \\ \\ \boxed{\boxed{ \green{ \sf \implies {PM}^{2} = QM.MR \: .}}}](https://tex.z-dn.net/?f=+%5Csf+%5Ctherefore++%5Ctriangle+PQM+%5Csim+%5Ctriangle+RPM.+%5C%5C++%5C%5C++%5Csf++%5Cimplies+%5Cfrac%7BPM%7D%7BMR%7D+++%3D++%5Cfrac%7BQM%7D%7BPM%7D+.+%5C%5C++%5C%5C++++%5Cboxed%7B%5Cboxed%7B+%5Cgreen%7B+%5Csf+%5Cimplies+%7BPM%7D%5E%7B2%7D++%3D+QM.MR+%5C%3A+.%7D%7D%7D)
✔✔ Hence, it is proved ✅✅.
THANKS
#BeBrainly.
▶Given :-
→ PQR is a right angle triangle .
→ Right angle at p .
→ PM
▶ To prove :-
→ PM² = QM • MR .
▶ Solution :-
We know that :
If a perpendicular is drawn from the vertex of the right angle of a right triangle to the hypotenuse then the triangles on both sides of the perpendicular and similar to the whole triangle and also to each other.
✔✔ Hence, it is proved ✅✅.
THANKS
#BeBrainly.
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![](https://hi-static.z-dn.net/files/d09/aa508a4be71869ad866d7f10916565c8.jpg)
sowmiya35:
thanks a lot
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