Question

Hi !

Solve this question ,given in the attachment .



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Answer 1

Step-by-step explanation:

$\sf {x}^{2} - x + 1 = 0$

$\sf Here\:a = 1 \:\:\:\: ; b = - 1 \:\:\:\: c = 1$

$\sf By \: formula \: method$

$\sf x = \frac { - b {+}_{-} \sqrt { {b}^{2} - 4ac}}{2a}$

$\sf x = \frac { 1 {+}_{-} \sqrt {{1}^{2} - 4(1)(1)}}{2}$

$\sf x = \frac { 1 {+}_{-} \sqrt {-3}}{2}$

$\sf\:Thus\: the\: roots \:are \: -\omega\: and\: - {\omega}^{2}$

$\sf \alpha = - \omega$

$\sf \beta = - { \omega}^{2}$

$\sf{\alpha}^{101} - {\beta}^{107}$

$\sf { - \omega}^{101} - { - {\omega}^{2}}^{107}$

$\sf - {\omega}^{2} - {\omega}$

- 1

THANKS!!!

Answer 2

Step-by-step explanation:

Hey!!!

@liferacer...

Thank you so much.....

#for thanking me#✍️