Math, asked by keerthana982006, 6 hours ago

hi this not answer Given the function f: x → x2 – 5x + 6, evaluate (i) f(-1) (ii) f(2a) (iii) f(2) (iv) f(x – 1) this ouestion ok vaa wait i am giving the answer Give the function f: x → x2 – 5x + 6. (i) f(-1) = (-1)2 – 5(1) + 6 = 1 + 5 + 6 = 12 (ii) f(2a) = (2a)2 – 5(2a) + 6 = 4a2 – 10a + 6 (iii) f(2) = 22 – 5(2) + 6 = 4 – 10 + 6 = 0 (iv) f(x – 1) = (x – 1)2 – 5(x – 1) + 6 = x2 – 2x + 1 – 5x + 5 + 6 = x2 – 7x + 12 ok vaa read propaley and give the court answer ok vaa this letter is for shreyahoodaO ok vaa

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Answered by manojchauhanma2
1

Give the function f: x → x2 – 5x + 6. (i) f(-1) = (-1)2 – 5(1) + 6 = 1 + 5 + 6 = 12 (ii) f(2a) = (2a)2 – 5(2a) + 6 = 4a2 – 10a + 6 (iii) f(2) = 22 – 5(2) + 6 = 4 – 10 + 6 = 0 (iv) f(x – 1) = (x – 1)2 – 5(x – 1) + 6 = x2 – 2x + 1 – 5x + 5 + 6 = x2 – 7x + 12Read more on f-2a-iii-f-2-iv-f-x-1

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