Question

Highest common factor = 2 x 2 = 4
EXERCISE 3.6
Q. 1. Find the H.C.F. of the following numbers :
(a) 18.48
(b) 30, 42 (c) 18, 60
(d) 27, 63
(e) 36, 84 (f) 34, 102
(g) 70, 105, 175 (h) 91, 112, 49
(i) 18, 54, 81 () 12, 45, 75.
Sol. (a) 18,48​

Answer 1

Answer:

(a)2

(B)6

(c)6

,(d)9

(e)12

(F)34

g 35

(h)7

(I)18

Answer 2

Answer:

H.C.F. (18, 48) = 2 x 3 = 6

Step-by-step explanation:

Solution:

(a) Factors of 18 = 2 x 3 x 3 (b) Factors of 30 = 2 x 3 x 5

Factors of 48 = 2 x 2 x 2 x 2 x 3 Factors of 42 = 2 x 3 x 7

H.C.F. (18, 48) = 2 x 3 = 6 H.C.F. (30, 42) = 2 x 3 = 6

(c) Factors of 18 = 2 x 3 x 3 (d) Factors of 27 = 3 x 3 x 3

Factors of 60 = 2 x 2 x 3 x 5 Factors of 63 = 3 x 3 x 7

H.C.F. (18, 60) = 2 x 3 = 6 H.C.F. (27, 63) = 3 x 3 = 9

(e) Factors of 36 = 2 x 2 x 3 x 3 (f) Factors of 34 = 2 x 17

Factors of 84 = 2 x 2 x 3 x 7 Factors of 102 = 2 x 3 x 17

H.C.F. (36, 84) = 2 x 2 x 3 = 12 H.C.F. (34, 102) = 2 x 17 = 34

(g) Factors of 70 = 2 x 5 x 7 (h) Factors of 91 = 7 x 13

Factors of 105 = 3 x 5 x 7 Factors of 112 = 2 x 2 x 2 x 2 x 7

Factors of 175 = 5 x 5 x 7 Factors of 49 = 7 x 7

H.C.F. = 5 x 7 = 35 H.C.F. = 1 x 7 = 7

(i) Factors of 18 = 2 x 3 x 3 (j) Factors of 12 = 2 x 2 x 3

Factors of 54 = 2 x 3 x 3 x 3 Factors of 45 = 3 x 3 x 5

Factors of 81 = 3 x 3 x 3 x 3 Factors of 75 = 3 x 5 x 5

H.C.F. = 3 x 3 = 9 H.C.F. = 1 x 3 = 3