Question

highest power of 2 in 1800×25×4^8×21^2×45^2​?

Answer 1

Answer:

19

Step-by-step explanation:

Answer 2

We must recall that:

$a^m\timesa^n=a^m^+^n$

Given:

$1800\times24\times4^8\times21^2\times45^2$

$=3^2\times2\times2^2\times5^2\times5^2\times2^1^6\times7^1\times3^1\times5\times3^2$

$=3^5\times2^1^9\times5^5\times7^1$

So highest power of $2$ is $19.$