Hii everyone!!!
Factorize the following
Plz help me....
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Answered by
7
9(2a-b)²- 4(2a-b) - 13
Let 2a-b = x
Now the equation becomes
9x²-4x-13
Factorising by splitting middle term
9x²-4x-13
9x²-13x+9x-13
(9x²-13x)+(9x-13)
x(9x-13)+1(9x-13)
(9x-13)(x+1)
putting value of x in the equation
[9(2a-b)-13][2a-b+1]
(18a-9b-13)(2a-b+1)
Answer - (18a-9b-13)(2a-b+1)
- Abhinav Singh
Let 2a-b = x
Now the equation becomes
9x²-4x-13
Factorising by splitting middle term
9x²-4x-13
9x²-13x+9x-13
(9x²-13x)+(9x-13)
x(9x-13)+1(9x-13)
(9x-13)(x+1)
putting value of x in the equation
[9(2a-b)-13][2a-b+1]
(18a-9b-13)(2a-b+1)
Answer - (18a-9b-13)(2a-b+1)
- Abhinav Singh
Sanskriti141:
how did u put the value of x in the equation
Answered by
12
Given Equation is 9(2a - b)^2 - 4(2a - b) - 13.
= > 9(2a^2 + b^2 - 2(2a)(b)) - 4(2a - b) - 13
= > 9(4a^2 + b^2 - 4ab) - 4(2a - b) - 13
= > 36a^2 + 9b^2 - 36ab - 8a + 4b - 13
= > 36a^2 - 36ab - 8a + 4b + 9b^2 - 13
= > 36a^2 - 18ab - 18ab + 18a - 26a - 9b + 13b + 9b^2 - 13
= > 18a(2a - b + 1) - 9b(2a - b + 1) - 13(2a - b + 1)
= > (18a - 9b - 13)(2a - b + 1).
Hope this helps!
= > 9(2a^2 + b^2 - 2(2a)(b)) - 4(2a - b) - 13
= > 9(4a^2 + b^2 - 4ab) - 4(2a - b) - 13
= > 36a^2 + 9b^2 - 36ab - 8a + 4b - 13
= > 36a^2 - 36ab - 8a + 4b + 9b^2 - 13
= > 36a^2 - 18ab - 18ab + 18a - 26a - 9b + 13b + 9b^2 - 13
= > 18a(2a - b + 1) - 9b(2a - b + 1) - 13(2a - b + 1)
= > (18a - 9b - 13)(2a - b + 1).
Hope this helps!
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