Physics, asked by rishiias, 1 year ago




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explain the Doppler effect

need relavistic effects

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Answers

Answered by fanbruhh
70
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DOPPLER'S EFFECT
Non - Relativistic Treatment
As most readers must have read in physics according to. This phenomenon the pitch sound observed by an observer is different in two cases, firstly when both the source and observer are stationary and secondly when there is relative motion between them. When source and observer are approaching each other, the apparent frequency is increased and when receding, decreased. This phenomenon is called doppler's effect which occurs with all kinds of wave motion, although in case of mechanical waves involving a material medium, its nature is some what different from the case of electromagnetic waves such as light where no medium is involved . In the case of light waves, if spectrum is observed in a spectrometer, a shift in the position of spectral line from the original position is observed with the motion of source.

we first consider the case when the observer is at rest and the source is moving towards it velocity u. let the frequency of the source be f so that the time period
T=1/f
and the wave speed be c in a time time interval T during which one cycle of wave is emitted the wave progresses a at distance cT but in the same period the source wave in the same direction distance u T hence wavelength which is distance between two successive maximum in the wave is cT-uT instead of cT.
Hence the corresponding frequency denoted by f1' its given by

f1'= c/ T(c-u)= cf/c-u

= f/ 1-(c/u)........ (1)

which represents and Apparent increase in the frequency if the source is moving away from the observer we put - u in place of u in equation( 1st) and get the corresponding f1'

in the second case When the source is stationary but the observer is moving with the velocity v from the source the wave is speed relative to the observer is not c but c-v and hence apparent frequency in the case is.

f \tiny{2} = \frac{c - v}{ \lambda} 
= c-v/c/f
= c-v/c*f

1 - \frac{v}{c} f \: .......(2)

now both observer and source are moving

\bf{\lambda \tiny{1} = \frac{c}{f \tiny{1}} }<br />= \: \frac{c - u}{ \lambda}

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1Angel25: Nice answer
fanbruhh: thanks
Swarnimkumar22: nice explained
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Answered by GreatBrainly
70
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Explain Doppler Effect.

Doppler Effect is an increase (or decrease) in the frequency of sound, light, or other waves as the source and observer move towards (or away from) each other. The effect causes the sudden change in pitch noticeable in a passing siren, as well as the red shift seen by astronomers.

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What are relativistic effect??

Relativistic effects are those discrepancies between values calculated by models that consider and that do not consider relativity. Relativistic effects are important for the heavier elements with high atomic numbers. In the most common layout of the periodic table, these elements are shown in the lower area.
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rishiias: great sir
fanbruhh: perfect
Anjula: Great Brainly its really a great wala !! epic :)
Newstudytiger: gh
1Angel25: Nice answer
ansari8097: how you did font
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