Hii Friends
Please Solve this Quasition And Share
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ritha1:
9+6+15=30
Answers
Answered by
1
Hey friend!
_____________
Here is your answer
___________________
When we add odd numbers, the result is always odd. Thus, we can use factorial method.
3! = 3 × 2 × 1
3! = 6
Thus, 6 + __ + __ = 30.
Now,
Let us substitute numbers in such a way that it full fills the condition.
Let us take 15 and 9
6 + 15 + 9 = 30
30 = 30
Therefore, LHS = RHS.
The numbers are, 3!, 15 and 9
( Note: You can check for more substitutes instead of 15 and 9)
_____________________________________________________________________
HOPE THIS HELPS YOU :)
_____________
Here is your answer
___________________
When we add odd numbers, the result is always odd. Thus, we can use factorial method.
3! = 3 × 2 × 1
3! = 6
Thus, 6 + __ + __ = 30.
Now,
Let us substitute numbers in such a way that it full fills the condition.
Let us take 15 and 9
6 + 15 + 9 = 30
30 = 30
Therefore, LHS = RHS.
The numbers are, 3!, 15 and 9
( Note: You can check for more substitutes instead of 15 and 9)
_____________________________________________________________________
HOPE THIS HELPS YOU :)
Answered by
2
Dear !!!
This type of question you can't solve with help of general method .
here question is saying ' sum of three odd numbers = even number
this isn't possible .
but when we use, factorial concept then you can solve this question easily .
now ,
we have given ,
1, 3 , 5 , 7, 9 , 11, 13 and 15
take first number 3 with factorial
e.g 3! = 3 × 2 × 1 = 6
take 2nd and 3rd number 11 and 13
then,
3! + 11 + 13 = 30
This type of question you can't solve with help of general method .
here question is saying ' sum of three odd numbers = even number
this isn't possible .
but when we use, factorial concept then you can solve this question easily .
now ,
we have given ,
1, 3 , 5 , 7, 9 , 11, 13 and 15
take first number 3 with factorial
e.g 3! = 3 × 2 × 1 = 6
take 2nd and 3rd number 11 and 13
then,
3! + 11 + 13 = 30
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