Question

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pllzzzz solve this question

Answer 1

Answer:

210,6

Step-by-step explanation:

Let the full fare be 'x'.

Then half the full fare be 'x/2'.

Let the reservation cost be 'y'.

Since a reserved first class ticket costs rs.216

x + y = 216   ----- (i)

One full and one half reserved ticket is 327.Each ticket will have its own reservation charge.

(x + y) + (x/2) + y = 327  

216 + (x/2) + y = 327

(x/2) + y = 111

x + 2y = 222   ---- (ii)

On solving (i) & (ii), we get

x + y = 216

x + 2y = 222

------------------

     -y = -6

      y = 6.

Substitute y = 6 in (i), we get

x + y = 216

x + 6 = 216

x = 210

Therefore:

Fare for first class ticket = 210.

Reservation cost = 6.

Hope this helps!

Answer 2

Step-by-step explanation:

Let half of the full basic fare be Rs. X.

Therefore, full basic fare is Rs. 2X.

Let the reservation charge be Rs. Y per ticket.

Now, one full reservation ticket would cost 2X (basic fare) + Y (reservation charge)

2X + Y = 216    --- (1)

The total basic fare for one half and one full ticket = X + 2X = 3X and the total reservation charge is 2Y.

Hence, 3X + 2Y = 327    --- (2)

Solving (1) and (2) we get,

X = 105 and Y = 6

Hence, the full basic fare is 2X = Rs. 210 and the reservation charge is Y = Rs. 6