hii frnds really need help in this.....
see attachment (-:
I hv got the ans but just confused whether the sign of ∆G will be +ve or -ve ? as the feasibility of reaction depends on that....pls just tell that only!
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Answers
del g is change in gibs free energy
so for feasible reaction delG is less than 0 so negative value come
Beforeng into free energy change calculations a little digression.
If the criteria for a feasible reaction is ΔStot >0 and ΔG<0 what is ΔG? and what is the connection between them?
PLEASE NOTE that you do not need to be able to derive the Gibbs free energy equation but I think it is important you realise there is a direct connection with the entropy expressions and that delta G expressions have not been pulled out of a hat!
From above and substituting: ΔSθtot = ΔSθsys –ΔHθsys/T, then multiplying through by T gives
TΔSθtot = TΔSθsys –ΔHθsys, then changing signs throughout gives
–TΔSθtot = –TΔSθsys + ΔHθsys
–TΔSθtot is called the Gibbs Free Energy change denoted by letter dellG