Question

hii guyzz ..gud mrng ..ans plz
in triangle ABC angle A = x° , angle B= (3x+2)° , angle C= y°
if angle C-B = 90° ..find all angles....​

Answer 1

solution:-

In △ ABC

∠A = x°, ∠B = (3x + 2)°, ∠C = y°

According to the Condition:-

If Angle C - Angle B = 90°

•°• ∠C - ∠B = y - (3x+ 2) = 90°

•°• y - 3x - 2 = 90

•°• 3x - y = - 90 - 2

•°• 3x - y = -92 .......1

sum of all angles of triangle is 180° :-

•°• x° + (3x + 2)° + y° = 180°

•°• x + 3x + 2 + y = 180

•°• 4x + y = 180 - 2

•°• 4x + y = 178 ........2

Adding equation 1 and 2 :-

3x - y = -92

+ 4x + y = 178

7x = 86

x = 86/7

x = 12.28°

substituting in 2:-

4x + y = 178

4 × 12.28 + y = 178

49.12 + y = 178

y = 178 - 49.12

y = 128.88°

The Angles of triangle ⬇️

∠A = x° = 12.28

∠B = (3x + 2)° = 3 × 12.28 + 2 = 36.84 + 2 = 38.84°

∠C = y° = 128.88°

Answer is appropriate due to decimal.

Answer 2

Answer:

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