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If two dices are thrown together
What is the probability of getting their sum as a prime number??
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S = ( 1, 1) , (1,2) , (1,4 ), (1,6) , (2,1 ), (2,3) , (2,5 ) , (3,2 ), (3,4) , (4,1) ,( 4,3 ), (5,2 ), (5,6 ), (6,1 ), (6,5)
P ( getting sum as prime number ) = 15 /36
= 5/12
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Answered by
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Answer:
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Step-by-step explanation:
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