hii mates plzz solve the following plzz plzz plzz thanx
Answers
First of all, below 60 means all below 60 and likewise.
So below 60 includes all those whose age of 60.
I am including the actual age relation in the picture attachment.
From the picture, the age group in which most of the people is in is 35 to 40 years.
So the median is 33.
The mode is the observation which occurs most frequently. It is 3. Refer to the picture.
The mean is the average of the total number of people divided by the number of age groups.
The mean is about 12.
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Answer:
Mean = 24.085
Mode = 65
Median = 35.75756
Step-by-step explanation:
Mean = {(Σfixi)/ (Σfi)}
Total No. of Observations Σfi = 100
Sum of Observations Σfixi = {(17.5*2)+(22.5*4)+(27.5*18)+(32.5*21)+(37.5*33)+(42.5*11)+(47.5*3)+(52.5*6)+(57.5*)}
=35+90+495+682.5+66+467.5+142.5+315+115
=2408.5
Mean = 2408.5/100
Mean = 24.085
Now,
Median = L + [{(N/2)-Pcf}/f}*h]
L = Lower Limit of Median class
N = Total No. of observations = 100
pcf= Cumulative fequency of preceeding median class
f = frequency of median class
h = size of the class interval
Median class = Class interval corresponding to Half of total no. of observations= C.I Correcsponding of Cumulative frequency 50
⇒Median Class = 35-40 (Since This is Interval whose cf is “JUST” grater than 50)
now h = 5
f = 33
pcf = 45
L = 35
So Median = 35 + [{(100/2)-45}/33}*5]
⇒Meidan = 35 + (5*5/33)
⇒Median = 1180/33
⇒Median = 35.75756
Now, Mode
Mode = L + [{(f0- f1)/(2 f0- f1- f2)}*h]
f0 = frequency of preceeding modal class
f1 = frequency of modal class
f2 = frequency of succeding modal class
L = Lower Limit of modal class
Modal Class = Class Interval Having Highest Frequency = 35-40
L = 35
f0 = 21
f1 = 33
f2 = 11
h = 5
Mode = 35 + [{(21- 33)/(2 *21- 33- 11)}*5]
Mode = 35 + 30
Mode = 65
Therefore, Mean = 24.085
Mode = 65
Median = 35.75756
