Question

Hii
Please answer the question fast
Class 9
please answer fast and CORRECT.
Correct answer :- BRAINLIEST
Incorrect answer :- REPORT
Please fast, I have to submit it tomorrow​​

Answer 1

Answer:

Let ABCD be the given trapezium in which AB = 25 cm, DC = 13 cm, BC = 10 cm and AD = 10 cm.

Through C, draw CE ∥ AD, meeting AB at E.

Also, draw CF ⊥ AB.

Now, EB = (AB - AE) = (AB - DC)

= (25 - 13) cm = 12 cm;

CE = AD = 10 cm; AE = DC = 13 cm.

Now, in ∆EBC, we have CE = BC = 10 cm.

So, it is an isosceles triangle.

Also, CF ⊥ AB

So, F is the midpoint of EB.

Therefore, EF = ¹/₂ × EB = 6cm.

Thus, in right-angled ∆CFE, we have CE = 10 cm, EF = 6 cm.

By Pythagoras’ theorem, we have

CF = [√CE² - EF²]

= √(10² - 6²)

= √64

= √(8 × 8)

= 8 cm.

Thus, the distance between the parallel sides is 8 cm.

Area of trapezium ABCD = ¹/₂ × (sum of parallel sides) × (distance between them)

= {¹/₂ × (25 + 13) × 8 cm²

= 152 cm²

Answer 2

Answer is = 152 centimeters square