Hii
Please answer the question fast
Class 9
please answer fast and CORRECT.
Correct answer :- BRAINLIEST
Incorrect answer :- REPORT
Please fast, I have to submit it tomorrow
Answers
Answer:
Let ABCD be the given trapezium in which AB = 25 cm, DC = 13 cm, BC = 10 cm and AD = 10 cm.
Through C, draw CE ∥ AD, meeting AB at E.
Also, draw CF ⊥ AB.
Now, EB = (AB - AE) = (AB - DC)
= (25 - 13) cm = 12 cm;
CE = AD = 10 cm; AE = DC = 13 cm.
Now, in ∆EBC, we have CE = BC = 10 cm.
So, it is an isosceles triangle.
Also, CF ⊥ AB
So, F is the midpoint of EB.
Therefore, EF = ¹/₂ × EB = 6cm.
Thus, in right-angled ∆CFE, we have CE = 10 cm, EF = 6 cm.
By Pythagoras’ theorem, we have
CF = [√CE² - EF²]
= √(10² - 6²)
= √64
= √(8 × 8)
= 8 cm.
Thus, the distance between the parallel sides is 8 cm.
Area of trapezium ABCD = ¹/₂ × (sum of parallel sides) × (distance between them)
= {¹/₂ × (25 + 13) × 8 cm²
= 152 cm²
Answer is = 152 centimeters square