Question

hii
please prove this theorem

Answer 1

hi dear here is the answer

We know that if two triangles are similar then the ratio of their corresponding sides are equal.

Hence, if triangle ABC is similar to triangle PQR, we have:

AB/ PQ = BC/ QR = AC/ PR

 

Now, using a property of ratios, we have:

AB/ PQ = BC/ QR = AC/ PR = AB+BC+CA/ PQ+QR+PR

 

Hence, the ratio of the perimeters of two similar triangles is the same as the ratio of their corresponding sides.

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Answer 2

$<b><font color = green>❤●••••☆Hہ۱او Uکer☆••••●❤ </font> 《《Here is your answer》》 <hr size = 3 width = 300 color = yellow ><font color = orange> The ratio of the perimeters of two similar triangles = the ratio of their corresponding sides. It can be proved. If Triangle ABC ~ Triangle XYZ AB/XY = BC/YZ = AC/XZ = K ( corresponding sides of similar triangles) => AB = K* XY ……… (1) BC = K * YZ ……….. (2) AC = K * XZ ………… (3) By adding (1), (2), & (3) AB + BC + AC = K ( XY + YZ + XZ) =>( AB + BC + AC)/(XY + YZ + XZ) = K => (Perimeter of tri ABC)/(perimeter of tri XYZ) = AB/XY = BC/YZ = AC/XZ = K </font> <hr size = 3 width = 300 color = yellow > <font color = green>❤●••••☆طraزnک۱۲tar☆••••●❤</font></b> <b>॰॰॰॰॰॰॰॥ॐ 卐 ☪ ✝☬ ॥॰॰॰॰॰॰॰</b>$