hii
please prove this theorem
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hi dear here is the answer
We know that if two triangles are similar then the ratio of their corresponding sides are equal.
Hence, if triangle ABC is similar to triangle PQR, we have:
AB/ PQ = BC/ QR = AC/ PR
Now, using a property of ratios, we have:
AB/ PQ = BC/ QR = AC/ PR = AB+BC+CA/ PQ+QR+PR
Hence, the ratio of the perimeters of two similar triangles is the same as the ratio of their corresponding sides.
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We know that if two triangles are similar then the ratio of their corresponding sides are equal.
Hence, if triangle ABC is similar to triangle PQR, we have:
AB/ PQ = BC/ QR = AC/ PR
Now, using a property of ratios, we have:
AB/ PQ = BC/ QR = AC/ PR = AB+BC+CA/ PQ+QR+PR
Hence, the ratio of the perimeters of two similar triangles is the same as the ratio of their corresponding sides.
hope it is helpful dear
mark me as brainlist
don't forget to follow me
Answered by
5
aman190k:
Thax
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