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PLZ SOLVE THIS
Answers
Let the cost of basic class full fare be 'x' and cost of reservation charge be 'y'.
(1) Given that one reserved first class ticket costs rs. 216.
= > x + y = 216 ------- (1)
(2) Given that one full and one half reserved first class tickets cost rs.327
= > x + y + (x/2) + y = 327
= > 2x + 2y + x + 2y = 327
= > 3x + 4y = 327 * 2
= > 3x + 4y = 654 ----- (2)
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On solving (1) * 3 & (2), we get
= > 3x + 3y = 648
= > 3x + 4y = 654
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-y = -6
y = 6.
Substitute y = 6 in (1), we get
= > x + y = 216
= > x + 6 = 216
= > x = 216 - 6
= > x = 210.
Therefore,
The basic class full fare ticket cost = 210.
The reservation charge = 6.
Hope this helps!