hii plzzz solve this problem, which term of AP : 3,8,13,15...is 78
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Answered by
2
AP : 3,8,13,15,...
a = 3 d = 8-3 = 5
An = 78
a+(n-1)d = 78
3+(n-1)5 = 78
(n-1)5 = 78-3 = 75
(n-1) = 75/5 = 15
n = 15+1 = 16
Hence,
16th Term of given AP is 78
a = 3 d = 8-3 = 5
An = 78
a+(n-1)d = 78
3+(n-1)5 = 78
(n-1)5 = 78-3 = 75
(n-1) = 75/5 = 15
n = 15+1 = 16
Hence,
16th Term of given AP is 78
1Farhana1:
thanks
Answered by
2
HEYA!!!!
Given,
series= 3,8,13,15...
a = 3
common difference (d) = a2 - a1
= 8-3
= 5
therefore common difference = 5
an = 78
a+ ( n-1) d = 78
3+(n-1) 5 = 78
3 + 5n - 5 = 78
5n - 2. = 78
5n = 78+2
5n = 80
n = 80/5
n = 16,,
Therefore, 78 is 16th term of given AP..
HOPE THIS HELPS U. @MP #MAHABOOBPASHA #☺☺
Given,
series= 3,8,13,15...
a = 3
common difference (d) = a2 - a1
= 8-3
= 5
therefore common difference = 5
an = 78
a+ ( n-1) d = 78
3+(n-1) 5 = 78
3 + 5n - 5 = 78
5n - 2. = 78
5n = 78+2
5n = 80
n = 80/5
n = 16,,
Therefore, 78 is 16th term of given AP..
HOPE THIS HELPS U. @MP #MAHABOOBPASHA #☺☺
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