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A particle of mass 10 grams is acted by a force of 150 dynes assuming that the particle starts from rest calculate the distance travelled in 10 seconds what is the velocity at the end of this period???
Answers
Answered by
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F=50 dynes or 0.0005 N[we have to convert it into Newtons (1 dyne = 10^-5 N)]
m=5 g (not necessary)
t=3 s
Impulse=?
FORMULA;
Impulse = F × t
SOLUTION;
Impulse= 0.0005 N × 3 s =0.0015 Ns or 1.5 × 10^-3 Ns
m=5 g (not necessary)
t=3 s
Impulse=?
FORMULA;
Impulse = F × t
SOLUTION;
Impulse= 0.0005 N × 3 s =0.0015 Ns or 1.5 × 10^-3 Ns
Answered by
1
hey mate here is your answer
F=50 dynes or 0.0005 N[we have to convert it into Newtons (1 dyne = 10^-5 N)]
m=5 g (not necessary)
t=3 s
Impulse=?
FORMULA;
Impulse = F × t
SOLUTION;
Impulse= 0.0005 N × 3 s =0.0015 Ns or 1.5 × 10^-3 Ns
mark me as a brainlist.....mate...
F=50 dynes or 0.0005 N[we have to convert it into Newtons (1 dyne = 10^-5 N)]
m=5 g (not necessary)
t=3 s
Impulse=?
FORMULA;
Impulse = F × t
SOLUTION;
Impulse= 0.0005 N × 3 s =0.0015 Ns or 1.5 × 10^-3 Ns
mark me as a brainlist.....mate...
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