Question

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Today's Question

=> The sum of three consecutive multiples of 8 is 888. Find these multiples?

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Answer 1

Let the first multiple of 8 be 8x.

Also the third consecutive multiple of 8 will be:--

8(x+2). => x = 36.

If we sum up these three multiples i.e

(288 + 296 + 304)

we get 888.

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Answer 2

Answer:

Let the first multiple of 8 be 8x.

Therefore the second consecutive multiple of 8 will be 8(x+1)

Also the third consecutive multiple of 8 will be 8(x+2).

It is given that the sum of these three consecutive multiples of 8 is 886

=> 8x + 8(x+1) + 8(x+2) = 888

=> 8x + 8x + 8 + 8x + 16 = 888

=> 24x + 24 = 888

=> 24x = 888 - 24

=> x = 864/24

=> x = 36.

Therefore First multiple of 8 be 8x = 8 x 36 = 288

Second Multiple of 8 be 8(x + 1) = 8(36 + 1) = 8 x 37 = 296

Third Multiple of 8 be 8(x + 2) = 8(36 + 2) = 8 x 38 = 304