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Q1 For any positive integer n, prove that n³-n is divisible by 6.
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Class 10th from ch1 extra question..!!
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Answered by
5
Hello dear user ✌️✌️
Here is your answer goes like this :
==================================================
ANSWER:
Given;
→ (n³-n)
Lets Put n = 1,we get
(1³-1) = 1-1 = 0 is divisible by 6
Lets Put n = 2,we get
(2³-2) = 8-2 = 6 is divisible by 6
Lets Put n = 3,we get
(3³-3) = 27-3 = 24 is divisible by 6
Lets Put n = 4,we get
(4³-4) = 64-4 = 60 is divisible by 6
Therefore,For any positive integer 'n', (n³ -n) is divisible by 6
HENCE PROVED.....
===========================================
I HOPE THIS WILL HELP YOU ✌️✌️
HAVE A GREAT DAY DEAR ✌️✌️
^_^
Here is your answer goes like this :
==================================================
ANSWER:
Given;
→ (n³-n)
Lets Put n = 1,we get
(1³-1) = 1-1 = 0 is divisible by 6
Lets Put n = 2,we get
(2³-2) = 8-2 = 6 is divisible by 6
Lets Put n = 3,we get
(3³-3) = 27-3 = 24 is divisible by 6
Lets Put n = 4,we get
(4³-4) = 64-4 = 60 is divisible by 6
Therefore,For any positive integer 'n', (n³ -n) is divisible by 6
HENCE PROVED.....
===========================================
I HOPE THIS WILL HELP YOU ✌️✌️
HAVE A GREAT DAY DEAR ✌️✌️
^_^
Anonymous:
Thanks a lot dear..!! ^_^
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2
Hey friend
here is your answer ⬆⬆
hope you understand
glad to help
thank you.
here is your answer ⬆⬆
hope you understand
glad to help
thank you.
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