Hiii friends....
Please answer me this question...
Calculate no.of atoms in 0.054g of aluminum.
please answer....
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no.of atoms
= number of moles × 6.023×10^23
= mass/molar mass × 6.023×10^23
= 0.054/27 × 6.023×10^23
= 2 × 10^-3 × 6.023×10^23
= 12.046 × 10^20
= 1.2046 × 10^21
= number of moles × 6.023×10^23
= mass/molar mass × 6.023×10^23
= 0.054/27 × 6.023×10^23
= 2 × 10^-3 × 6.023×10^23
= 12.046 × 10^20
= 1.2046 × 10^21
pavamuruganpbcfes:
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