Math, asked by ItZcandycaneSweety, 7 months ago

Hiii guys!!✌✌

If x + y = 12 and xy = 14, find the value of (x^2 + y^2).

Plz solve it ⬆️⬆️

Answers

Answered by Anonymous
1

Answer:

Given - X+ y= 12

Xy = 14

to find - X^2 + y^2

solution -

X+y= 12

(X+y)^2 = 12^2

X^2 +y^2 +2xy= 144

X^2 + y^2 + 2(14) = 144

X^2 + y^2 +28= 144

X^2 + y^2 = 144-28

X^2 + y^2= 116

Answered by ScienceMathsLover
1

Answer:

130

Step-by-step explanation:

 {x}^{2}  +  {y}^{2}  =  {(x + y)}^{2}  - xy

We already have the values so substitute them..

 {x}^{2}  +  {y}^{2}  =  {(12)}^{2}  - 14 = 144 - 14 = 130

Hence ur answer is 130...

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