Question

m=10kg | u=100m/s | v=200m/s | t=10 seconds
find:-
1.change in momentum
2.force

whoever gives the best answer i will mark u as brainliest , give u thanks , rate for u !!!​

Answer 1

Given:

Mass,m= 10kg

Initial velocity,u= 100 m/s

Final velocity,v= 200 m/s

Time taken,t= 10s

To Find:

1. Change in momentum

2. Force

Solution:

We know that,

• Expression of change in momentum(Δp) is given by

$\pink{\underline{\boxed{\bf{\triangle p=m(v-u) }}}}$

• Expression of acceleration(a) is given by

$\purple{\underline{\boxed{\bf{a=\dfrac{v-u}{t}}}}}$

• Expression of Force(F) is given by

$\orange{\underline{\boxed{\bf{F=ma}}}}$

where

m is mass

v is final velocity

u is initial velocity

t is time taken

━━━━━━━━━━━━━━━━━━━━━

Let the change in momentum be Δp

So,

$\longrightarrow\rm{\triangle p=m(v-u) }$

$\longrightarrow\rm{\triangle p=10(200-100) }$

$\longrightarrow\rm{\triangle p=10(100) }$

$\longrightarrow\rm\green{\triangle p=1000\ kg\ m/s}$

━━━━━━━━━━━━━━━━━━━━━

Let the acceleration be a

So,

$\longrightarrow\rm{a=\dfrac{v-u}{t}}$

$\longrightarrow\rm{a=\dfrac{200-100}{10}}$

$\longrightarrow\rm{a=\dfrac{100}{10}}$

$\longrightarrow\rm{a=10\ m/s^{2}}$

Let the force be F

So,

$\longrightarrow\rm{F=ma}$

$\longrightarrow\rm{F=10\times10}$

$\longrightarrow\rm\green{F=100\ N}$

Answer 2

$\huge\underline{\pink{A}\blue{N}\orange\green{S}\red{W}\purple{E}\blue{R}}$

Given:

Mass,m= 10kg

Initial velocity,u= 100 m/s

Final velocity,v= 200 m/s

Time taken,t= 10s

To Find:

1. Change in momentum

2. Force

Solution:

We know that,

Expression of change in momentum(Δp) is given by

momentum(Δp) is given by

$\red{\underline{\boxed{\bf{\triangle p=m(v-u) }}}}$

Expression of acceleration(a) is given by

$\pink{\underline{\boxed{\bf{a=\dfrac{v-u}{t}}}}} </p><p>$

Expression of Force(F) is given by

$\blue{\underline{\boxed{\bf{F=ma}}}} </p><p></p><p> </p><p>$

where

m is mass

v is final velocity

u is initial velocity

t is time taken

━━━━━━━━━━━━━━━━━━━━━

Let the change in momentum be Δp

So,

$\longrightarrow\rm{\triangle p=m(v-u)$

$\longrightarrow\rm{\triangle p=10(200-100) }$

$\longrightarrow\rm{\triangle p=10(100) }$

$\longrightarrow\rm\green{\triangle p=1000\ kg\ m/s}$

━━━━━━━━━━━━━━━━━━━━━

Let the acceleration be a

So,

$\longrightarrow\rm{a=\dfrac{v-u}{t}}$

$\longrightarrow\rm{a=\dfrac{200-100}{10}}$

$\longrightarrow\rm{a=\dfrac{100}{10}}$

$\longrightarrow\rm{a=10\ m/s^{2}}$

Let the force be F

So,

$\longrightarrow\rm{F=ma}$

$⟶F=10×10$

$⟶F=100 N$