Question

Hiii !!!

Solve 3rd no . question given in this aatachment !!

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Step by step Solution needed ✔

Answer 1

It vanishes, so the eqn must equate to 0.
For this, log2logπ(x) must equate to 1 as loga(1)=0
This implies logπ(x) must equate to 2 as loga(a)=1
Hence logπ(x)=2 and x=π²

Answer 2

Final Answer : x = π^2 :

Steps:
1)
$log_{7}( log_{2}( log_{\pi}(x) ) ) = 0 \\ = > ( log_{2}( log_{\pi}(x) ) ) = {7}^{0} = 1 \\ = > log_{\pi}(x) = {2}^{1} \\ = > x = {\pi}^{2}$